12/18/2017 · Graph v/s 1/u and 1/v in concave mirror .. Graphical representation in optics…=====lecture for the exam pr…
7/29/2019 · For convex mirror . Since convex mirror always produced virtual image, option (d) is not correct. For virtual image v > 0 ,u 0 . Let 1/v = y, 1/f = c and 1/u = -x ? y = c + x , this is represented by graph (iii). Thus option (c) is correct. For Concave mirror. 1/u + 1/v = 1/f ? 1/v = 1/f – 1/u. For virtual image v > 0, u 0.
as for mirror formula . u 1 + v 1 = f 1 and f is constant. The relation between u 1 and v 1 is a linear relation, and . For a convex lens v 1 ? u 1 = f 1 v u u ? v = f 1 (u ? v) (v u) = f The above equation looks like a hyperbola. Hence correct answer is A as negative u gives positive v.
9/27/2019 · U vs V graph for convex and concave lens, 1/u vs 1/v graph for convex and concave lens,Ray optics class 12 full lectureshttps:// www .youtube. com /playlist?list=…
Draw graph between 1/v against 1/u: Solution: (1) Concave mirror:-(1) Real image. ? 1 /v + 1/u = 1/f ? 1/v = 1/u + 1/f ? y = – mx + c (2) Virtual image. ? 1/f = 1/v + 1/u ? 1/v = 1/u – 1/f ? y = mx – c (2) Convex mirror :-(1) Virtual image. ? 1/+f + 1/+v + 1/-u ? 1/v = 1/u + 1/f ? y = my + c. Refer the attachment for the graphs.
A bright point S is on the principal optical axis of a concave mirror of radius R = 4 0 c m at d = 3 0 c m from its pole. At what distance (in cm) in front of the concave mirror should a plane mirror be placed so that after two reflections, the rays converge back at point S.
